14x^2-38x-12=0

Solution for 14x^2-38x-12=0 equation:

14x^2-38x-12=0

a = 14; b = -38; c = -12;
Δ = b2-4ac
Δ = -382-4·14·(-12)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-46}{2*14}=\frac{-8}{28}
=-2/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+46}{2*14}=\frac{84}{28}
=3
$